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Mathematics 17 Online
OpenStudy (darkbluechocobo):

Help please. Much confusion

OpenStudy (darkbluechocobo):

Ok so I did \[\frac{ 16\pi }{ 3}-2\pi = \frac{ 10\pi }{ 3 }\]

OpenStudy (darkbluechocobo):

so based on this. I am confused

OpenStudy (darkbluechocobo):

or did i do this wrong all together. Because I am not sure if this was a 60 degree or 30 degree cause the steps are different

OpenStudy (jhannybean):

\[\frac{16\pi}{3} -2\pi = \frac{16\pi}{3}-\frac{6\pi}{3} = \frac{10\pi}{3} -2\pi = \frac{10\pi}{3}-\frac{6\pi}{3} = \frac{4\pi}{3}\]We had to reduce the radians by \(2\pi\) to fit it between the range of \(0 \rightarrow 2\pi\) \(\dfrac{4\pi}{3}\) lies in the 3rd quadrant so what would its coordinate points be?

OpenStudy (darkbluechocobo):

im really confused about the sectors

OpenStudy (darkbluechocobo):

and also would be -1/2,-sqrt3/2

OpenStudy (jhannybean):

What do you mean by 'sectors'?

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