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OpenStudy (anonymous):
Which is a solution to the inequality?
y < -2/3x + 2
(0, 2)
(3, 0)
(0, 0)
(0, 3)
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OpenStudy (misty1212):
hi
we can try them !
OpenStudy (misty1212):
if you pput \(x=0,y=2\) you get
\[2<0+2\] which is not right so it is not that one (unless it was really \(\leq \))
OpenStudy (misty1212):
if you put \(x=3\) and \(y=0\) up get
\[0<-\frac{2}{3}\times 3+2\\
0<-2+2\\
0<0\] also not right
OpenStudy (anonymous):
OH i get it now! ill try the last two options myself will you tell me if i get it right?
OpenStudy (anonymous):
sorry i had to log off earlier, but its C right?
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sammixboo (sammixboo):
So, is the inequality \(\le\) or \(<\)? Just curious
OpenStudy (anonymous):
the second option :)
sammixboo (sammixboo):
Because sometimes it makes it look weird to make it look like a negative sign
sammixboo (sammixboo):
KK I was curious :) Anyways, you think it is C?
OpenStudy (anonymous):
yes i do think so :0
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sammixboo (sammixboo):
You are correct! Plug in the answers and check if you want! :)
OpenStudy (anonymous):
yes thats what i did !! :)
sammixboo (sammixboo):
Okie Dokie! :)
OpenStudy (anonymous):
thank you though btw
sammixboo (sammixboo):
No problem!!
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sammixboo (sammixboo):
If you need anymore help tag me @sammixboo or Misty @misty1212
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