Which is a solution to the inequality? y < -2/3x + 2 (0, 2) (3, 0) (0, 0) (0, 3)
hi we can try them !
if you pput \(x=0,y=2\) you get \[2<0+2\] which is not right so it is not that one (unless it was really \(\leq \))
if you put \(x=3\) and \(y=0\) up get \[0<-\frac{2}{3}\times 3+2\\ 0<-2+2\\ 0<0\] also not right
OH i get it now! ill try the last two options myself will you tell me if i get it right?
sorry i had to log off earlier, but its C right?
So, is the inequality \(\le\) or \(<\)? Just curious
the second option :)
Because sometimes it makes it look weird to make it look like a negative sign
KK I was curious :) Anyways, you think it is C?
yes i do think so :0
You are correct! Plug in the answers and check if you want! :)
yes thats what i did !! :)
Okie Dokie! :)
thank you though btw
No problem!!
If you need anymore help tag me @sammixboo or Misty @misty1212
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