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sec theta = -4√7/7 Find sin(2theta) if cdc theta is greater than 0
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hi
draw a triangle, make the hypotenuse \(4\sqrt7\) and the adjacent side \(7\)
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all that is missing is \(b\) which you find by pythagoras \[b=\sqrt{(4\sqrt{7})^2-7^2}=\sqrt{63}\]
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now you can take any trig ratio you want
ooh you want \[\sin(2\theta)\]
that is \[2\sin(\theta)\cos(\theta)\] we can find it in a second
Thank you!
but first what does cdc theta is greater than 0 mean?
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anyways \[\cos(\theta)=-\frac{7}{4\sqrt7}\] and \[\sin(\theta)=\frac{\sqrt{63}}{4\sqrt{7}}\]
plug them in above and see what you get when you simplify \[2\times -\frac{7}{4\sqrt7}\times \frac{\sqrt{63}}{4\sqrt{7}}\]
how did you get sqrt 63?
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