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Mathematics 9 Online
OpenStudy (anonymous):

Conditional Probability Help

OpenStudy (anonymous):

OpenStudy (anonymous):

Exactly.

OpenStudy (anonymous):

9

OpenStudy (anonymous):

14

OpenStudy (anonymous):

how so

OpenStudy (anonymous):

@swagmaster47 Shouldn't we just ask him how many people were there in all, and then ask for the people who visited the museum and didn't go to the zoo?

OpenStudy (anonymous):

Ugh I don't even think I'm understanding myself...

OpenStudy (anonymous):

im a girl

OpenStudy (anonymous):

Nope! Only the people who visted the museum.

OpenStudy (perl):

thats pretty cool how you marked a perfect red oval there

OpenStudy (anonymous):

Magic mspaint

OpenStudy (anonymous):

Sorry. @Starr_DynastyT :P

OpenStudy (anonymous):

...

OpenStudy (anonymous):

Paint.net > MS Paint :P

OpenStudy (anonymous):

you dont have to apologize @AnswerMyQuestions

OpenStudy (anonymous):

;P

OpenStudy (anonymous):

Add 9 + 5 @Starr_DynastyT

OpenStudy (anonymous):

14

OpenStudy (anonymous):

Yes.

OpenStudy (turingtest):

who you guys, @AnswerMyQuestions was right before you need to consider only people that did not visit the zoo

OpenStudy (turingtest):

whoa*

OpenStudy (anonymous):

I was? :D

OpenStudy (anonymous):

ok im really trying to be one place but im getting confused

OpenStudy (anonymous):

Yeah, I guess we are confusing her...

OpenStudy (anonymous):

@TuringTest You can take over... :P

OpenStudy (turingtest):

yes, conditional probability means you only consider the "universe" in which the given event is true is what we need to consider

OpenStudy (turingtest):

we know that the people we are concerned about did not visit the zoo, therefor all the people that visited the zoo are not important to he problem, hence we are considering only the first row

OpenStudy (anonymous):

ok understanding

OpenStudy (turingtest):

http://prntscr.com/5pwt0f

OpenStudy (turingtest):

so how many people total did not visit the zoo?

OpenStudy (anonymous):

5

OpenStudy (anonymous):

?

OpenStudy (turingtest):

no number of people that didn't visit the zoo = people that visited museum and not zoo + people who visited neither museum nor zoo

OpenStudy (turingtest):

argh museum

OpenStudy (turingtest):

sorry

OpenStudy (anonymous):

i subtracted 9 from 14

OpenStudy (turingtest):

I don't understand the logic of why you subtracted

OpenStudy (turingtest):

wrong one sorry

OpenStudy (turingtest):

http://prntscr.com/5pwus2

OpenStudy (turingtest):

those are the people that visited the zoo and the museum

OpenStudy (anonymous):

i see 9

OpenStudy (turingtest):

these are the people who visited the zoo and not the museum http://prntscr.com/5pwvss

OpenStudy (anonymous):

theres 1`4

OpenStudy (turingtest):

so how many total visited the zoo?

OpenStudy (anonymous):

or 23

OpenStudy (turingtest):

23 is correct and out of those 23 people, how many went to the museum?

OpenStudy (anonymous):

14

OpenStudy (misty1212):

hi

OpenStudy (anonymous):

HEEYYY!!!!

OpenStudy (misty1212):

is this the same problem as at the top of the page?

OpenStudy (misty1212):

probability that the person visited the museum given that they did not visit the zoo?

OpenStudy (anonymous):

Yes it is

OpenStudy (misty1212):

this is not really that hard at all first we find out how many people did NOT visit the zoo by adding \(5+2\) to get \(7\) out of those 7 we see that 5 visited the museum

OpenStudy (misty1212):

then compute the ratio \(\frac{5}{7}\) i guess with a calculator since they want the answer as a percent

OpenStudy (anonymous):

71.43%

OpenStudy (anonymous):

Yessss!

OpenStudy (anonymous):

thats it?

OpenStudy (anonymous):

Yep. You always take what's given to be your denominator in the fraction. Then the area in question as your nominator. Divide to find your %. I'd be happy to help more if you need it!

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