Question

Math HW help! @Clalgee help!

Answer 1

Hi! What can I do for you?

Answer 2

Give me a second and I will post the question.

Answer 3

Alright.

Answer 4

Alright so here we go.

BH is perpendicular to AC. Find x the length of BC.

Answer 5

Alright, so do you know where to start?

Answer 6

Negative Sherlock.

Answer 7

Ok. I will help you start off.

BH perpendicular to AC means that triangles ABH and HBC are right triangles, am I right?

Answer 8

Your right.

Answer 9

So that means that : tan(39*) = 11 / AH or AH = 11 / tan(39*)

Answer 10

So now, fill in the blanks.

? = ? - AH = 19 - ? / tan(39*)

Answer 11

HC I think. 19. and 11?

Answer 12

Perfect! So now we will set these of to the side for now.

Answer 13

Pythagora's theorem applied to right triangle HBC: \[11^ 2+HC=X^2\]

Answer 14

Do you think you can solve for X?

Answer 15

No.... :(

Answer 16

Aw, just give it a try. Give it your best go!

Answer 17

ok

Answer 18

x = sqrt [ 112 + (19 - 11 / tan(39o) )2 ]

Answer 19

O.o Wow! You didn't even need my help! great job! What will that give you?

Answer 20

Haha! But I didn't even know where to start!

and I think its 12

Answer 21

Close! You have to round it by the 3rd number. Now what would your answer be?

Answer 22

12.3!!

Answer 23

Yes! NIce job! You did an awesome job!

Answer 24

Thank yo sooo much! Your a lifesaver!