MEDAL!!!
Figure ABCD is a parallelogram with point C (3, -2). What rule would rotate the figure 90 degrees counterclockwise, and what coordinate would be the output for point C'? Possible answers: (x, y) → (-y, -x); C' (2, -3) (x, y) → (y, -x); C' (-2, -3) (x, y) → (y, x); C' (-2, 3) (x, y) → (-y, x); C' (2, 3)
Can you clarify the question marks.
Sorry, Thats what my laptop did... Its not supposed to mean anything... ignore it...
Okay, let me think.
The formula would be: (x, y) goes to (y, -x). So: Now, due to how y is already negative that means if you were to rotate it 90 degrees it should be (3, 2) or (2, 3), but it could also be (-2, -3) Based off of the answer I would say B: (y, -x) (-2, -3)
Another one:
Alright.
If quadrilateral ABCD is congruent to quadrilateral EFGH, then what corresponding side is congruent to side FG? Possible answers: Side AB Side BC Side CD Side DA
Well, a picture would greatly help, but I would assume it would be: B. Side BC - But, you should attempt to show me the quadrilaterals.
I got the first question wrong and the second one correct! Thanks for helpin. @Ghostgate
Dang, sorry I didn't give you the right answer for the first one. I'm guessing it was D I bet.
Ya, It was D. Thank you anyways!
You're welcome! ;)
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