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Last question of the night guys! :)
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Question #14 Somewhat same as the last one!
this one is the easiest of the lot replace \(n\) by \(1\) and see what you get
you are not a famous basketball player are you?
Sadly, I am not :( Why do you ask?
no you are too young to be that kristen rasmussen in any case all the terms are negative, and you have \[-\frac{2}{3},-(\frac{2}{3})^2,-(\frac{2}{3})^3\] as the first three terms
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go with A
Hahaha I wish I were a famous basketball player! Thank you for all of your help tonight!
\[\large a_{\color{red}{n}}=(-1)\left(\frac{2}{3}\right)^{\color{red}{n}}\]\[\large a_{\color{red}{n}}=a_{\color{red}{1}}~,~a_{\color{red}{2}}~,~a_{\color{red}{3}}... \]
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