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Mathematics 16 Online
OpenStudy (anonymous):

Help me solve this equation. Just show the work and I will understand it!

OpenStudy (anonymous):

\[\sqrt{2x+3}=1+\sqrt{x+1}\]

OpenStudy (jhannybean):

First of all, 2 things you need to know: 1. Getting rid of a square root, you need to square it, so: \((\sqrt{2x+3})^2\) , do the same thing to the RHS. 2. the RHS of the equation is in the form \((a+b)\), and once you square both sides of your eqaution fro step 1, you will end up with \((a+b)^2\) on the right side.\[(a+b)^2 = a^2+b^2 +2ab\]

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