Question

Can some please help me put this in standard form? I'm pretty sure it's a parabola, but I'm confused on how to get this tin standard.

y^2+4x-6y+5=0

Answer 1

well standard form is A+B=C

Answer 2

I would say the standard form is 3+2sqrt-x+1

Answer 3

=y

Answer 4

\[y=3\pm2\sqrt{-x+1}\]

Answer 5

Ax+By=C and C will be 5

Answer 6

you guys mind helping me? 1/2 + 3/2d = -1/d I got 11

Answer 7

4x-5y^2=5

Answer 8

@Avonniculley post it as a different question