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Mathematics 12 Online
OpenStudy (anonymous):

You flip a coin twice. Find the probability that at least one of the tosses showed heads.

OpenStudy (anonymous):

ok i typing the choices now

OpenStudy (anonymous):

A. 3/4

OpenStudy (anonymous):

B. 1/4

OpenStudy (mathmate):

Hints: When the problem is P("at least...") most of the time you can solve it quickly by 1-P("not even...") So solving probability of at least once head is the same as solving 1-Prob.(not even one head). Yes, 3/4 is correct.!

OpenStudy (anonymous):

ok well i have one more so plz help me

OpenStudy (anonymous):

OpenStudy (anonymous):

. 0.560 B. 0.110 C. 0.216 D. 0.440

OpenStudy (anonymous):

A. is the first one

OpenStudy (anonymous):

I'm gonna say B

OpenStudy (mathmate):

Sorry, B is not the one. When it says P(pink given 30-39) it means P(pink|30-39) which is a conditional probability. @Imtrying

OpenStudy (mathmate):

Conditional probability P(A given B)=P(A}B)=P(A\(\cap\) B)/P(B) can you work that out?

OpenStudy (mathmate):

* P(A|B) instead of P(A}B)

OpenStudy (anonymous):

oh so d

OpenStudy (mathmate):

Yes, well done!

OpenStudy (anonymous):

im thinking that because i actually rolled the dice and did it

OpenStudy (mathmate):

That great! It's called a random experiment!

OpenStudy (mathmate):

But you cannot do that for the second question! :(

OpenStudy (anonymous):

well i have 15 more but ill let u go but thxs

OpenStudy (anonymous):

You were alot of help!

OpenStudy (mathmate):

You're welcome! Try them by yourself, I think you can handle them!

OpenStudy (anonymous):

ok

OpenStudy (mathmate):

Bye!

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