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Mathematics 19 Online
OpenStudy (anonymous):

help! simplify the rational expression?

OpenStudy (anonymous):

if someone could let me know how to start solving this that would be great!

OpenStudy (anonymous):

just cant remember what to do first^

Miracrown (miracrown):

So with any rational expression, it's a good bet that we can cancel terms. in order to do that, we need to try and factor wherever possible

Miracrown (miracrown):

So first, on top, can we factor x^2+4x-21?

OpenStudy (anonymous):

yes i think..im not great at factoring! im actually quite bad at it.

OpenStudy (anonymous):

7 and -3? so would that turn into (x+7) (x-3)

Miracrown (miracrown):

Right!

Miracrown (miracrown):

Now we do the same thing on bottom. We'll have two factors (since the biggest power is 2)

OpenStudy (jhannybean):

Can you write your function out bigger please/ It's too tiny.

Miracrown (miracrown):

...and we need two numbers that multiply to get -42 and add up to 1 (for 1x in the middle)

OpenStudy (jhannybean):

is it \(\dfrac{x^2+4x-21}{x^2+x-42}\)?

OpenStudy (anonymous):

hmm well it has to be 42 and 1 right?

OpenStudy (anonymous):

what else adds up to be 1 but multiplies to 42? hahah

OpenStudy (anonymous):

Jhanny, yes it is. it is a picture though, if you click on it it should come up bigger.

Miracrown (miracrown):

Can you think of two numbers that multiply to get 42 but are one away from each other?

OpenStudy (anonymous):

i feel like it has to be simple but i cant think of anything

OpenStudy (anonymous):

21 and 2 get 42 but wont equal 1..hmm

Miracrown (miracrown):

Need a hand?

OpenStudy (anonymous):

yes sadly i think so hahah

Miracrown (miracrown):

6 and 7 :)

OpenStudy (anonymous):

oh my gosh yup it was simple

Miracrown (miracrown):

and will it be x+7 and x-6 or x-7 and x+6

OpenStudy (anonymous):

haha okay thank you. so now its (x+7) (x-3)/(x+7)(x-6)

OpenStudy (anonymous):

ooh and then the x+7 cancels out

OpenStudy (anonymous):

ah thank you so much! i may actually have some others, if i do i will tag you in them! i really appreciate the help!

Miracrown (miracrown):

And what do we have left?

OpenStudy (anonymous):

(x-3)/(x-6) :)

OpenStudy (anonymous):

or C^

Miracrown (miracrown):

Yes! That's right!And yw :)

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