Question

MEDAL TO BEST ANSWER

Given three consecutive integers with a sum of four times the second number, write an algebraic equation for this situation.

n + n + 1 +n + 2 = 4n
n + n + 1 + n + 2= = 4(n+1)
3n+3=4n

Answer 1

@Directrix. Last question if you could help.

Answer 2

What is all this, your answer?

n + n + 1 +n + 2 = 4n n + n + 1 + n + 2= = 4(n+1) 3n+3=4n

Answer 3

It is the answer options

Answer 4

okay. I thought it was the last one, but, based on a different problem, that I can post if you want, the answer was similar to the second one.

Answer 5

I had to finish up a problem I had helped a guy get started on before you called me.

Answer 6

The three consecutive integers are:
n
n + 1
n + 2

Answer 7

Here is the problem that is similar that also has my teacher's feedback.

Given five consecutive integers with a sum of three times the second number, write an algebraic equation for this situation.
5n + 5 = 3n ----answer I chose
n + n + 1 + n + 2 + n + 3 + n + 4 = 3(n + 1) --correct answer
(n + 1)^5 = 3n
N + n + 1 + n + 2 + n + 3 + n + 4 = 3n

FEEDBACK:
When you translate this expression into math terms, the result is: n + n + 1 + n + 2 + n + 3 + n + 4 = 3(n + 1)
Rebember that, given that the first term is n, the consecutive integers are ( n + 1), (n + 2), and so on. Therefore, the “second number” is (n+1)

Answer 8

Hopefully that helps. I think it is the second answer but I need to be sure.

Answer 9

Now, we have to translate the words of the problem to mathematical symbols.

three consecutive integers with a sum
======================

n + n+1 + n + 2


a sum of four times the second number,
=========================

4*(n+1)

Answer 10

How (mathematical operation) are these two expressions related?

n + n+1 + n + 2

and

4*(n+1)

Answer 11

@BeccaB003

Answer 12

They are related because it is a sum of four numbers times the second number which is n...

Answer 13

So, what equation would you write to illustrate that?

Answer 14

n + n + 1 + n + 2= 4(n+1)

Answer 15

Correct.

Answer 16

thanks!

Answer 17

You're welcome.