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(side)^2 + (side)^2 = (hypotenuse)^2
I have this question and one more then I'm done, I just need to know how to do these lol.
That is the pythagorean theorem for right triangles sum of the squares of the two sides = hypotenuse squared
15^2 + 20^2?
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yes = (AB)^2
so AB = square root (15^2+20^2)
25?
\[a^2 + b^2 = c^2\] \[c = \sqrt{a^2 + b^2}\]
yep
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Yayyyyy lol :)
Same thing with this one?
kind of
\[30^2 = 24^2 + BC^2\]
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need to subtract this time instead
they gave you the hypotenuse and a leg length, instead of both leg lengths
\[BC = \sqrt{30^2-24^2}\]
18 cm? I got that by putting 18 squared + 24 squared = 30 squared. 30 squared is 900
right
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Thank you so much for helping me Dan :)
you're welcome
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