Question

@perl

Answer 1

can you please check my answer??

Answer 2

I feel like there's not enough information. We don't know what the initial position is.

Answer 3

integrate, and assume initial position is zero

Answer 4

This is a calculus problem, correct?

Answer 5

You can't just assume that. :3

Answer 6

yes

Answer 7

it says first 2 sec, it is the change in position over 2 seconds

Answer 8

\[\int\limits_{0}^{2}v(t)dt = ...\]

Answer 9

is it 4?

Answer 10

yeah , i think so

Answer 11

thanks(:

Answer 12

Yeah, I guess you can consider it means what the change is in 2 seconds.

Answer 13

i just said 0 to 2 seconds, because it said "first two seconds of travel"