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OpenStudy (anonymous):
If 2x^2+10x+6=6, which of the following could be the value of x+5?
I. 1
II. 5
III.10
The Answer is 5 but how is that the answer?
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OpenStudy (anonymous):
@mathmath333
OpenStudy (mathmath333):
\(\large\tt \begin{align} \color{black}{
2x^2+10x+6=6\hspace{.33em}\\~\\
}\end{align}\)
OpenStudy (mathmath333):
\(\large\tt \begin{align} \color{black}{
\implies 2x^2+10x=0\hspace{.33em}\\~\\
}\end{align}\)
OpenStudy (anonymous):
Alright subtract six. Would you then solve for x?
OpenStudy (mathmath333):
yes of cos
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OpenStudy (anonymous):
Of cosine?
OpenStudy (mathmath333):
lol , i mean of course
OpenStudy (anonymous):
Oh my bad hah. Alright so
OpenStudy (anonymous):
\[2x(x+5)\]
OpenStudy (mathmath333):
sry this one
\(\large\tt \begin{align} \color{black}{
\implies 2x(x+5)=0\hspace{.33em}\\~\\
\implies x(x+5)=0\hspace{.33em}\\~\\
\implies x=0~~~or~~~x+5=0\hspace{.33em}\\~\\
}\end{align}\)
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OpenStudy (anonymous):
Alright thta's what I got x=0 and x=-5
OpenStudy (mathmath333):
yes but the question asks
\(\large\tt \begin{align} \color{black}{
(x+5)=?\hspace{.33em}\\~\\
}\end{align}\)
OpenStudy (anonymous):
oh yes that's right
OpenStudy (anonymous):
That's where I'm confused.
OpenStudy (mathmath333):
we found
\(\large\tt \begin{align} \color{black}{
x=0\hspace{.33em}\\~\\
}\end{align}\)
add \(5\) to both sides
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OpenStudy (anonymous):
so
x+5=5?
OpenStudy (anonymous):
oh dam haha that's the answer XD
OpenStudy (mathmath333):
yes that should be it the options dont have \(0\) as the answer
OpenStudy (anonymous):
Thank you very much!
OpenStudy (mathmath333):
yw
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OpenStudy (mathmath333):
is is probably a trick question
OpenStudy (mathmath333):
*this is
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