If 2x^2+10x+6=6, which of the following could be the value of x+5? I. 1 II. 5 III.10 The Answer is 5 but how is that the answer?
@mathmath333
\(\large\tt \begin{align} \color{black}{ 2x^2+10x+6=6\hspace{.33em}\\~\\ }\end{align}\)
\(\large\tt \begin{align} \color{black}{ \implies 2x^2+10x=0\hspace{.33em}\\~\\ }\end{align}\)
Alright subtract six. Would you then solve for x?
yes of cos
Of cosine?
lol , i mean of course
Oh my bad hah. Alright so
\[2x(x+5)\]
sry this one \(\large\tt \begin{align} \color{black}{ \implies 2x(x+5)=0\hspace{.33em}\\~\\ \implies x(x+5)=0\hspace{.33em}\\~\\ \implies x=0~~~or~~~x+5=0\hspace{.33em}\\~\\ }\end{align}\)
Alright thta's what I got x=0 and x=-5
yes but the question asks \(\large\tt \begin{align} \color{black}{ (x+5)=?\hspace{.33em}\\~\\ }\end{align}\)
oh yes that's right
That's where I'm confused.
we found \(\large\tt \begin{align} \color{black}{ x=0\hspace{.33em}\\~\\ }\end{align}\) add \(5\) to both sides
so x+5=5?
oh dam haha that's the answer XD
yes that should be it the options dont have \(0\) as the answer
Thank you very much!
yw
is is probably a trick question
*this is
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