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Mathematics 7 Online
OpenStudy (anonymous):

amelia sets her CD player to randomly select songs from the 4 CD's she has loaded. Disc A has 8 songs, disc B has 10 songs, disc C has 7 songs, and disc D has 12 songs. what is the probability that the first song she hears is from disc C?

OpenStudy (anonymous):

@Directrix

Directrix (directrix):

what is the probability that the first song she hears is from disc C? ======================= Well, there are 4 discs in the player. I think each disc is equally likely to be selected. And, I think that the number of songs per disk does not matter. But, I need someone else on OS to read the question and see what he or she thinks about it.

OpenStudy (anonymous):

hmmm let me see

OpenStudy (anonymous):

@thesmartone

Directrix (directrix):

It seems that we are selecting discs and not songs. Four discs and we want one of them which would make me think the probabillity would be 1/4. I would like to hear what @kropot72 has to say but he will not be on until later tonight.

OpenStudy (anonymous):

well its an assignment and once i leave it then i cant finish it

OpenStudy (anonymous):

and @TheSmartOne is online i just dont know why he isnt coming

Directrix (directrix):

For the first song Amelia hears to be from disc C, then disc C would have to be chosen first. So, I am going with 1/4.

OpenStudy (anonymous):

well, lets see what thesmartone has to say

Directrix (directrix):

Another approach would be to add all the songs on all four discs: 8 + 10 + 7 + 12 Of those, 7 are on disc C

TheSmartOne (thesmartone):

Hmm. I really don't know. It sounds confusing.. @Jhannybean @Nnesha Want to try this problem?

OpenStudy (anonymous):

geez......

Directrix (directrix):

7/( 8 + 10 + 7 + 12) (The problem is poorly written.)

TheSmartOne (thesmartone):

^ that was what I was thinking.

Directrix (directrix):

I think the problem writer was thinking that also. So, let's go with it.

TheSmartOne (thesmartone):

Maybe @iambatman can save the day. :)

Directrix (directrix):

Not knowing the selection process of this machine is confusing.

OpenStudy (anonymous):

well i cant fail this assignment -.-

Directrix (directrix):

Understood.

TheSmartOne (thesmartone):

I wonder if it has to do with permutations and combinations..

Directrix (directrix):

Looking at the question again: >> randomly select songs from the 4 CDs I am convinced that the answer is 7/37 --> 7 songs on disc C and 37 total songs on the 4 discs. @mcnabkt

OpenStudy (anonymous):

oh okay so how do we solve it?

Directrix (directrix):

Perhaps one of the onlookers will post an idea.

OpenStudy (anonymous):

-.-

OpenStudy (anonymous):

|dw:1421011357853:dw|

OpenStudy (anonymous):

so , the first song is from CD# C |dw:1421011582872:dw| means we are picking one out of 4 p(first song from C )=1/4

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