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In set-builder notation, how do you write the solutions of the inequality? 3x 10 *>=* 4 A) {x|x*>=*-2} B) {x|x*<=* 2} C) {x|x*<=*-2} D) {x|x*>=* 2}
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3x 10 *>=* 4 can you clarify that?
*>=* is greater than or equal to
3x 10 what does that mean?
3 with the letter x , not multiply
what's the operation with 10 then?
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oh whoops its 3x + 10 *>=* 4
\[3x+10\ge4 \]
correct?
yea
alright so you just solve for x here. 3x+10>=4 subtract the 10 3x>=-6 divide by and you get..?
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1x*>=*=-3
-6/3=?
-2
so it should be x>=-2
so A ?
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@dtan5457
yes
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