Question

if f(x)= 3x^2-4x+1 and g(x)= 3x^2-3 what values are not in the domain of f/g? A. 0 B. 1 C. 3 D. +-1 E. no values to exclude?

Answer 1

HI

Answer 2

we need to put
\[3x^3-3=0\] and solve
we gotta be careful here

Answer 3

\[3x^2-3=0\\
3x^2=3\\
x^2=1\\
x=\pm1\]

Answer 4

Well we have f/g=\[\Large \frac{ 3x^2-4x+1 }{ 3x^2-3 }\]

Answer 5

say everything but those two numbers

Answer 6

We also have to look for numbers in the numerator that make it undefined and numbers in the denominator that are undefined or 0(as that will make it like a number divided by 0)

Answer 7

Are there any numbers that will make the numerator 3x^2-4x+1 undefined?