Question

will fan and medal. Suppose a parabola has vertex (–4, 7) and also passes through the point (–3, 8) How would you write this in vertex form?

Answer 1

do u know the standard equation of vetex form??/

Answer 2

it is :
y=a(x-h)^2 + k where (h,k) is vertex...

Answer 3

now u cn solve?

Answer 4

y=(x+4)^2 +7 ?

Answer 5

correct..:)

Answer 6

Can you help me with 2 more?

Answer 7

yeah sure

Answer 8

Write the expressions in factored form.
9x^2-4
4x^2+11x+6
6x^2+4x
x^2+13x+42

Answer 9

we have three basic forms...:
\[a ^{2} - b ^{2} = (a+b)(a-b)\]
\[(a+b)^{2} = a ^{2} +2 a b + b ^{2}\]
\[(a-b)^{2}=a ^{2}-2ab+b ^{2}\]

Answer 10

so our first question is of first form.. solve and tell..

Answer 11

for second question its splitting of middle term... do u know how to do it?

Answer 12

in third question... see we can take something out common... so take common out.. put else in bracket....

Answer 13

and fourth is again splitting...

Answer 14

i have no idea where to start though

Answer 15

okk... for first question:
we can write as (3x)^2 - (2)^2

Answer 16

understood?

Answer 17

not really?

Answer 18

so 6x^2+4x would be 2x(3x + 2)

Answer 19

right ,....