will fan and medal. Suppose a parabola has vertex (–4, 7) and also passes through the point (–3, 8) How would you write this in vertex form?

Question

anonymous · Answer

do u know the standard equation of vetex form??/

anonymous · Answer

it is :
y=a(x-h)^2 + k   where (h,k) is vertex...

anonymous · Answer

now u cn solve?

madgirlwithabluebox · Answer

y=(x+4)^2 +7 ?

anonymous · Answer

correct..:)

madgirlwithabluebox · Answer

Can you help me with 2 more?

anonymous · Answer

yeah sure

madgirlwithabluebox · Answer

Write the expressions in factored form. 
9x^2-4
4x^2+11x+6
6x^2+4x
x^2+13x+42

anonymous · Answer

we have three basic forms...:
$$a ^{2} - b ^{2} = (a+b)(a-b)$$
$$(a+b)^{2} = a ^{2} +2 a b + b ^{2}$$
$$(a-b)^{2}=a ^{2}-2ab+b ^{2}$$

anonymous · Answer

so our first question is of first form.. solve and tell..

anonymous · Answer

for second question its splitting of middle term... do u know how to do it?

anonymous · Answer

in third question... see we can take something out common... so take common out.. put else in bracket....

anonymous · Answer

and fourth is again splitting...

madgirlwithabluebox · Answer

i have no idea where to start though

anonymous · Answer

okk... for first question:
we can write as (3x)^2 - (2)^2

anonymous · Answer

understood?

madgirlwithabluebox · Answer

not really?

madgirlwithabluebox · Answer

so 6x^2+4x would be 2x(3x + 2)

anonymous · Answer

right ,....