Question

Equation posted inside. calculus integral

Answer 1

give me a min to get the equation in

Answer 2

\[\int\limits 6re^r/3 dr\]

Answer 3

i can post what i have so far but I will need a min for that too. Jordan are you here?

Answer 4

By parts, regardless of whether you meant
\[\int6re^{r/3}\,dr\quad\text{or}\quad\int6r\frac{e^r}{3}\,dr\]

Answer 5

i meant the first one you wrote

Answer 6

u= 6r dv= e^r/3 du= 6dr w= r/3 dr= 3dw v= 3e^ r/3

Answer 7

6r (3e^r/3) - integral 3 e^r/3 (6dr)
= 18 re^r/3 - 18 integral e^r/5 dr

Answer 8

this is where i get stuck

Answer 9

\[18 r e^\frac{ r }{ 3 } - 18 \int\limits e^\frac{ r }{ 5 } dr\]