Question

I'm in desperate need of help. Pre-calc; I'm trying to study for my final and would really appreciate it if someone could explain how to do this.

The equation for the asymptote when the transverse axis is horizontal is: y= (+-) b/a (x-h) +k

The equation for the asymptote when the transverse axis is vertical is: y= (+-) a/b (x-h) +5

Using this information, write the equation of the hyperbola.

15. Vertices: (0, -1), (0,1) Asymptotes: y= 1/3x, y= -1/3x

16. Vertices: (-6,0), (6,0) Asymptotes: y= 4/3x, y= -4/3x

Answer 1

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