solving systems with substitution?
yes, you can
elimination is mostly better.
oops, I meant to put the link to the problem: https://31.media.tumblr.com/0c6d5f3bb262275c0bf252984770fd89/tumblr_inline_ni57gs28ib1qh9byg.png
I prefer elimination, but this one calls for substitution specifically, and I just can't figure out how to do this problem :/
you are given in the third equation that x is same as -3z. So you can substitute -3z instead x into every other (1st and 2nd) equations.
\(\large\color{blue}{ 3x+y-22=22 }\) \(\large\color{blue}{ x+5y+z=4 }\) substitution, \(\large\color{blue}{ 3(-3z)+y-22=22 }\) \(\large\color{blue}{ (-3z)+5y+z=4 }\)
is my latex working for u, because it isn't for me...
I can't solve down very far, I just get y=11z+22 for the top equation and a complicated fraction for the second
@SolomonZelman any other ideas?
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