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Mathematics 12 Online
OpenStudy (anonymous):

HELP !!! What is the simplest form of the expression? 3[14 / (4^2 - 3^2) - 5] A) -9 B) 27 C) 21 D) 6

OpenStudy (anonymous):

ok so how would you begin?

OpenStudy (anonymous):

PEMDAS so ( )'s

OpenStudy (anonymous):

yep! good, so how would you work the inside of the brackets?

OpenStudy (anonymous):

btw what does PEMDAS stand for?

OpenStudy (anonymous):

so we cannt looking at 3[14 / (4^2 - 3^2) - 5] we are looking at this 14 / (4^2 - 3^2) - 5

OpenStudy (anonymous):

( )'s Exponents Multiplication, Division Addition, Subtraction

OpenStudy (anonymous):

ah cool, so back to you question :) what would you work out first in this? 14 / (4^2 - 3^2) - 5

OpenStudy (anonymous):

parentheses Exponents Multiplication, Division Addition, Subtraction

OpenStudy (anonymous):

So it'd now be 14 / (16 - 9) - 5

OpenStudy (anonymous):

continue! going great!

OpenStudy (anonymous):

then 14 / 7 - 5

OpenStudy (anonymous):

Then 2 - 5

OpenStudy (anonymous):

then 3 x -3 = -9 ???

OpenStudy (anonymous):

so A ?

OpenStudy (anonymous):

sry wasnt focusing lol checking now! xD

OpenStudy (anonymous):

ya

OpenStudy (anonymous):

i think

OpenStudy (anonymous):

and it's (14 / 7) - 5 and not 14 / (7-5) ?

OpenStudy (anonymous):

which is it? cause it matters

OpenStudy (anonymous):

true da

OpenStudy (anonymous):

u askin me ?

OpenStudy (anonymous):

yep, was the question 3[14 / ((4^2 - 3^2) - 5)] or 3[(14 / (4^2 - 3^2)) - 5] ?

OpenStudy (anonymous):

There was no double ( )'s

OpenStudy (anonymous):

like was the -5 part of the denominator or no?

OpenStudy (anonymous):

the -5 part was . . .3^2) -5 ]

OpenStudy (anonymous):

3[14 / (4^2 - 3^2) - 5] 3[14 / (16 - 9) - 5] 3[14 / (7) - 5] from there is where the brackets aren't clear if the next step is 3[ 2 - 5] or 3[14 / 2] get it?

OpenStudy (anonymous):

cause idk if only 7 is the denominator in the question of 7 - 5 was the denominator

OpenStudy (anonymous):

this is the original problem 3[14 / (4^2 - 3^2) - 5]

OpenStudy (anonymous):

|dw:1421204117491:dw| or |dw:1421204219445:dw|

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