WILL MEDAL: -Linear Equation- Write the following in standard from: y-3 = (-1/4)(x+4). I got: x + 4y = 4. Please double check my answer. Thanks.

Question

calculusfunctions · Answer

The right side of your final answer is incorrect. It's not 4.

anonymous · Answer

y-3 = (-1/4)(x+4)
y = -(1/4)x + (4/4) + 3
Since (-1/4) = -(1/4); then -(1/4)(4) = +(4/4)?

anonymous · Answer

y = -(1/4)x + (4/4) + 3
y = -(1/4)x + (16/4)
x + 4y = 16?

anonymous · Answer

y = -(1/4)x + (-4/4) + 3

calculusfunctions · Answer

No, in your former response, when you expanded, you should have y = -(1/4)x - (4/4) + 3

anonymous · Answer

I'm getting my signs fudge up again
So: x + 4y = -1?

anonymous · Answer

Damn it -8?

anonymous · Answer

y = -(1/4)x + (-1) + 3
y = -(1/4)x + 2

calculusfunctions · Answer

No, look$$y -3=\frac{ -1 }{ 4 }(x +4)$$$$y =-\frac{ 1 }{ 4 }x -1+3$$$$y =-\frac{ 1 }{ 4 }x +2$$Now multiplying both sides by 4 yields$$4y =-x +8$$Thus$$x +4y =8$$

calculusfunctions · Answer

So you see your error.

calculusfunctions · Answer

Anything else I can assist you with?

anonymous · Answer

Yes thanks. I'll just post another question if I need help in anything else.