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(6-2x)^2-144=0 Can you help me understand how you solve this and why you solve it in such a way.
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This is a quadratic equation. You can solve it using the quadratic formula. Check this out. http://www.purplemath.com/modules/quadform.htm
X=-9,-3
a simple step is to add 144 to both sides of the equation \[(6 - 2x)^2 = 144\] then take the square root of both sides \[6 - 2x = \pm 12\] which can become 6 - 2x = 12 and 6 - 2x = -12 so solve both equations to get the solutions to the equations.
http://i.gyazo.com/7bf6fc045a918679b3b59fc6c1f78c77.png how do you know if the 9 and the 3 is possitive or negative
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