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Mathematics 8 Online
OpenStudy (anonymous):

The length of a rectangle is 4 times its width and the perimeter is 150 feet. What is the width of the rectangle? A. 75 feet B. 60 feet C. 30 feet D. 15 feet

OpenStudy (anonymous):

@zzumfelde009

OpenStudy (campbell_st):

set up an equation w = width l = length you are told the length is 4 times the width so l = 4w then the perimeter P = 2 l + 2w when you substitute is 150 = 2(4w) + 2w or 150 = 10w now solve for w.

OpenStudy (anonymous):

sooooo... what the width? O-O

OpenStudy (campbell_st):

well just solve the equation 150 = 10w

OpenStudy (anonymous):

how?

OpenStudy (anonymous):

d

OpenStudy (anonymous):

just set up an equation in terms of some width w. For 1) suppose the width is w and the length is 4w. Since the perimeter of the rectangle is 150 feet, we have 2(w + 4w) = 150 --> 10w = 150 --> w = 15. The width is 15

OpenStudy (anonymous):

its D? thx

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

thx

OpenStudy (campbell_st):

to solve the equation 150 = 10w divide both sides of the equation by 10

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