Question

Please HELP!! PROMISE A MEDAL!!!

A side of a house is in the shape of a triangle on top of a rectangle. The rectangle is four times as long as it is high, and the altitude of the triangular part is 1 m greater than the height of the rectangle. The total area of the side of the house is 60 square meters. Find the height of this side of the house.

Answer 1

did you draw this thing up and try to put the given information on it yet?

Answer 2

of course but it doesn't make sense @DanJS

Answer 3

ok let e try and sketch it up here

Answer 4

Let the height of the rectangle be h, the other two measurements relate to that height

Answer 5

It says:
The rectangle is four times as long as it is high: h = height we defined
length is 4 times that or 4*h

Answer 6

the altitude of the triangular part is 1 m greater than the height of the rectangle
height we defined as h
so the altitude of the triangle is h + 1

Answer 7

good on how all those measurments were added to the picture?

Answer 8

yes THANK YOU SO MUCH i feel so stupid now thank you again!!!

Answer 9

What is the formula for the total area of both those figures added together?

Answer 10

Triangle = 1/2 * (base)*height = (1/2)*4h *(h+1)
Rectangle = base * height = 4h * h

Total Area = Triangle Area + Rectangle Area

\[60 = \frac{ 1 }{2 }*4h*(h+1) + 4h*h\]

Answer 11

is that what you did?

Answer 12

yes thank you again i got the problem

Answer 13

what is h=
i just figured it, you get two answers, but only one is reasonable

Answer 14

h=3

Answer 15

yep same here, you can add those to the diagram as a double check if you want

Answer 16

60 = 12*3 + 0.5*12*4 TRUE, h=3 is right

Answer 17

tag me another if you have more, these are kinda fun probs

Answer 18

ok i will thank you again