Question

show that when
\(n=(a+b)=a^2-b^2\)
then n is odd .

Answer 1

@mathmath333

Answer 2

(a+b) is not equal to a^2 - b^2 ^.^ >,<
^.~

Answer 3

^_^ cute

Answer 4

it can

Answer 5

for example :

2 + 1 = 2^2 - 1^2

Answer 6

yeah but........... ~.^
a^2 - b^2 = (a+b) this is right but its also (a -b) :D:D

Answer 7

hmmmmm bye

Answer 8

this observation makes u solve it @Nnesha

Answer 9

yes i see now

Answer 10

thats a good starting point

Answer 11

\(\large\tt \begin{align} \color{black}{a^2-b^2=a+b\hspace{.33em}\\~\\
(a+b)(a-b)=a+b \hspace{.33em}\\~\\
(a-b)=1 \hspace{.33em}\\~\\
a=b+1 \hspace{.33em}\\~\\
n=a+b \hspace{.33em}\\~\\
n=b+1+b \hspace{.33em}\\~\\
n=2b+1 \hspace{.33em}\\~\\
n(mod~2)=(2b+1)(mod~2)\hspace{.33em}\\~\\
n(mod~2)\equiv 1\hspace{.33em}\\~\\
}\end{align}\)

n is odd

Answer 12

:D yes yes

Answer 13

thnks thnks :)

Answer 14

np np ;)

Answer 15

nice nice

Answer 16

okay i'm back :D

Answer 17

hmmm O_O that mod thingy :O
what is mod ??? mod ganeshie8 ??

Answer 18

@nnesha

Answer 19

@Marki

Answer 20

what mod thingy ?
mod in the question is modules :) or residues

Answer 21

:O:P okay

Answer 22

a2−b2=a+b (a+b)(a−b)=a+b (a−b)=1 a=b+1 n=a+b n=b+1+b
n=2b+1 oaky so i got this one what you did after this n(mod 2) ????

Answer 23

n=2b+1 means n is odd :)

Answer 24

\(\Huge \color{red}{\heartsuit}\)

Answer 25

hmmmm marki law of love with math lololol

Answer 26

^_^

Answer 27

n(mod 2)=(2b+1)(mod 2)
n(mod 2)≡1 <---------- so how he./she got 1 here ?? :O

Answer 28

Any integer of form \(2a + 1\) is odd, where \(a\) is some integer

Answer 29

Any integer of form \(2a\) is even, wher e \(a\) is some integer

Answer 30

yeah mod means residues , when u divide 2b+1 over 1 would left , right ?

Answer 31

those are the definitions of odd and even numbers