Matt has $200 in his bank checking account. Each month he deposits $300 into his account. Matt needs to accumulate more than $4200 for a car that costs for a used car that costs.
Solve, using algebraic transformations, the equation that you chose 300x + 200 4200.

Question

Matt has $200 in his bank checking account.  Each month he deposits $300 into his account. Matt needs to accumulate more than $4200 for a car that costs for a used car that costs.
Solve, using algebraic transformations, the equation that you chose 300x + 200 > 4200.

directrix · Answer

As before, this sentence does not read right.

Read it and tell us what it means if it is posted correctly.

>> Matt needs to accumulate more than $4200 for a car that costs for a used car that costs.

directrix · Answer

@sodumbineedhelp Is this the problem: Matt has $200 in his bank checking account. Each month he deposits $300 into his account. Matt is saving up for a used car that costs $4200. A. Look at the algebraic equations below. Which equation can be solved to find out the number of deposits Matt needs to accumulate more than $4200? (1 point) 200x + 300 > 4200 300x + 200 > 4200 200x + 300 < 4200 300x + 200 < 4200

directrix · Answer

Commentary from @RoofingPrincess

A. Matt starts out with $200. Then he adds $300/month for x months. So you need an equation with 300x + 200, which rules out the first and third equations. He needs to end up with more than $4200, so it's 300x + 200 > 4200