Question

HELP ME!!!
As Mercury revolves around the sun, it travels at a speed of approximately
30
miles per second. Convert this speed to kilometers per second. At this speed, how many kilometers will Mercury travel in 20 seconds? In your computations, assume that
1 mile is equal to 1.6 kilometers. Do not round your answers.

Answer 1

@DanJS please help meee

Answer 2

do 30*1.6 that's going to get you kilometers per sec.

Answer 3

then do that * 20

Answer 4

so it would be 960 if you multiply that

Answer 5

that's rounded though

Answer 6

30x1.6= 48

Answer 7

48x90=960 @rocklionmba

Answer 8

that's your answer

Answer 9

you answered you own question

Answer 10

is 960 the speed or is it the distance traveled in 20 miles? @rocklionmba

Answer 11

distance; 48 is speed

Answer 12

so what is the distance traveled in 20 miles? @rocklionmba

Answer 13

960 is distance, 48 is speed

Answer 14

hi

Answer 15

you still working on this?

Answer 16

heyyyy

Answer 17

yeahh please help mee

Answer 18

do you think the answer i have is correct?

Answer 19

I say yes

Answer 20

i think he is right too

Answer 21

start with what you are given, 20 seconds, multiply that by ratios of 1 to cancel units correctly , and end with kilometers, like above

Answer 22

1 mi = 1.6 km
30 mi = 1 sec

Answer 23

mhmm okay then what i do?

Answer 24

after you set it up and the units cancel correctly, take care of all the numbers now

Answer 25

multiply all the top mumbers and divide by all the bottom numbers

Answer 26

if you want just the speed in km/s only do the first 2 of the 3 fractions, you are left with km/s

Answer 27

for speed i got 48 is that correct?

Answer 28

\[\frac{ 30~mi }{ 1~s }*\frac{ 1.6~km }{ 1~mi } = \frac{ km }{ s }\]

Answer 29

miles cancel, left with km/s

Answer 30

For conversion probs and things like this, set up fractions multiplied together, and take care of the units first, if the units work out correctly, then you have the right answer

Answer 31

for the distence traveled i got 960 km/s is that correct?? @DanJS