Question

HALP D: https://vvsd6966-vvagpeap-ccl.gradpoint.com/Resource/6114359,67D,0,0,0,0,0/Assets/74794_53c6cc08/image0044e848638.gif
What is the volume of grain that could completely fill this silo, rounded to the nearest whole number? Use 22/7 for pi.

Answer 1

@Mertsj

Answer 2

The formula for the volume of the cylinder is:
\[V=\pi r^2h\]

Answer 3

The volume of the half sphere is:
\[V=\frac{1}{2}\times \frac{4}{3} \pi r^3\]

Answer 4

Calculate those two values and add them together.

Answer 5

What numbers do I plug in where?Sorry I'm a bit new at this so I have no clue on what to do.

Answer 6

What is the radius of the cylinder?

Answer 7

6 feet

Answer 8

Then replace r with 6 in the cylinder formula.
What is the height of the cylinder?

Answer 9

168ft

Answer 10

Then replace h with 168 in the cylinder formula.

Answer 11

What is the radius of the half sphere?

Answer 12

6ft?

Answer 13

Then replace r with 6 in the half sphere formula.

Answer 14

So the cylinder is V=pi 6^2 168?

Answer 15

Um. So it's pi x 36 x 168? @Mertsj

Answer 16

@sleepyhead314

Answer 17

yes, that is right for the cylinder :)

Answer 18

okay so it should be 19000.3523.....etc

Answer 19

hmmm that's the more accurate answer which is good
but I think they want you to use 3.14 as pi :/

Answer 20

i did

Answer 21

well i used the pi button XD

Answer 22

yeah but if you do just 3.14
I got 18990.72 instead :P

Answer 23

yeah I just got that too

Answer 24

ok and then we add the half sphere

Answer 25

(1/2)*(4/3)*(3.14)*(radius)^3

Answer 26

(1/2)*(4/3)*(3.14)*(6)^3?

Answer 27

yes :)

Answer 28

um so it should be .5 x 1.33 x 3.14 x 6 x 6 x 6

Answer 29

hehe yes
which I got as 452.16

Answer 30

o3o same now what do I do?

Answer 31

18990.72 + 452.16 =

Answer 32

ok

Answer 33

19442.88

Answer 34

right! :) then round to whole number

Answer 35

19,008 ft3
19,461 ft3
6,336 ft3
453 ft3


These are my answer choices

Answer 36

19, 461?

Answer 37

*scratches head* yeah, that's the closest one xD

Answer 38

XDDDDD