Solve the following equations

$$X ^{2} +4x-11=0$$

Question

Solve the following equations 

$$X ^{2} +4x-11=0$$

mathmath333 · Answer

$\large \begin{align} \color{black}{ x^2+4x+11=0 \hspace{.33em}\~\
}\end{align}$

anonymous · Answer

what do you mean@mathmath333

mathmath333 · Answer

i mean is the $x$ in small case letters

mathmath333 · Answer

by squaring method
$\large \begin{align} \color{black}{ x^2+4x+11=0 \hspace{.33em}\~\
\implies  x^2+2\cdot 2x+2^2-2^2+11=0 \hspace{.33em}\~\
\implies x^2+4x+4-4+11=0 \hspace{.33em}\~\
\implies (x+2)^2+7=0 \hspace{.33em}\~\
}\end{align}$

mathmath333 · Answer

see if it makes sense so far

anonymous · Answer

thx

mathmath333 · Answer

lol its not the full answer its only partially solved

mathmath333 · Answer

continuing further

$\large \begin{align} \color{black}{ (x+2)^2+7=0 \hspace{.33em}\~\
 (x+2)^2-(-7)=0 \hspace{.33em}\~\
 (x+2)^2-(\sqrt{7i})^2=0 \hspace{.33em}\~\
\left( x+2-\sqrt{7}i\right) \times (x+2+\sqrt{7}i)=0  \hspace{.33em}\~\
 x=-2+\sqrt{7}i~~~or~~~x=-2-\sqrt{7}i \hspace{.33em}\~\
}\end{align}$

nnesha · Answer

lol mathmat3333