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@Directrix
We have a pair of sides and a pair of angles given as marked on the original angle. Do you see where we can get a second pair of congruent sides. Look at the original diagram?
MN?
Yes, if you mark that side MN, you'll see that it is shared by both triangles and is congruent to itself by the reflexive property. So, which postulate?
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SAS?
Yes, that is what I got.
same and thanks again for the help
As usual, you are welcome.
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