Question

A number is chosen at random from the first 100 positive integers. Find the probability that the number is either even or a perfect square.


11/20

1/20

Answer 1

@trindawg

Answer 2

\[P \left( A \cup B \right)=P(A)+P(B)-P(A~intersection ~B)\]
A= event even no.
B=event perfect square.
A={2,4,6,8,....,98,100},n(A)=50
B={1,4,9,16,25,36,49,64,81,100},n(B)=10
A intersection B={4,16,36,64,100},n(A intersection B )=5
\[P(A \cup B )=?\]

Answer 3

\[P(A \cup B)=\frac{ 50 }{ 100 }+\frac{ 10 }{ 100 }-\frac{ 5 }{ 100 }=?\]

Answer 4

1/2+1/10-1/20=?

Answer 5

the ways @surjithayer wrote is better :)

Answer 6

11/20?

Answer 7

correct.

Answer 8

thnx

Answer 9

seems to me you just guessed heheh