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Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles. C = 67, a = 21, c = 20
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@satellite73
|dw:1421617850637:dw|
man that is one ugly picture, but i hope you get the idea
Yep, I get it
using the law of sines you get \[\frac{\sin(67)}{20}=\frac{\sin(A)}{21}\]
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when you take the arcsine you will get the acute A
What would I take arcsin of? That is what is giving me trouble. :/
you want angle A
\[\sin(A)=\frac{21\sin(37)}{20}\] so that is what you need to find the arcsine of to find A
but the arcsine obviously gives you only one answer the acute one
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