Question

Closed Question.

Answer 1

@iambatman have a look here please.... help him...

Answer 2

If a quadrilateral is a parallelogram, then the diagonals bisect each other.

To force the given quadrilateral to be a parallelogram, you must find values of x and y that will do that.

Answer 3

So, solve this system for x and y: @Night-Watcher

3x - 6 = x + 12
y + 12 = 6y - 8
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Answer 4

I see that there is one variable here: y + 12 = 6y - 8

So, solve that for y first.

Answer 5

Does y= 4?

Answer 6

And does x=9?

Answer 7

I'm feelin really confident about these...

Answer 8

I agree with (9,4). @Night-Watcher

Answer 9

Okay, Thanks!

Answer 10

You are welcome.