what is the domain and the range of f(x)=1/x+1
get zero's of this function to get domain. then get its inverse and get its domain thus you will get is range
?
why are you sticking with that? domain is all numbers except which make the function undefined.
is it all real numbers except for 1?
Are you asking if the domain or range is all real numbers except for 1? And why do you think that?
is the domain all real numbers except for 1?
your function is 1/(x+1) right? if x=1, then you have 1/(1+1)=1/2 is 1/2 not a number?
I think you are thinking about the opposite of 1 -1 (x+1) is what you don't want to be zero since you can not divide by zero and we know x+1=0 when x=-1
the range is kinda easy to find here too we have 1/(x+1) hint: we know the only thing that will ever make a fraction 0 is the top
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