Mathematics
8 Online
OpenStudy (dtan5457):
How do I solve absolute value inequalities like this again?
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OpenStudy (dtan5457):
\[-3\left| 6-x \right|<-15\]
Miracrown (miracrown):
Divide -3 on both sides first
OpenStudy (dtan5457):
do i divide inside the absolute value too?
OpenStudy (dtan5457):
completely forgot this..
OpenStudy (freckles):
let u=|6-x|
-3u<-15 <--- do you know how to solve this for u?
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Miracrown (miracrown):
Then we have |6-x|>5.
No, we don't.
OpenStudy (dtan5457):
@freckles
Yeah, divide both by -3 and switch the sign
OpenStudy (freckles):
right and you what @Miracrown just posted u>5
Miracrown (miracrown):
We need to get rid of absolute value sign
Miracrown (miracrown):
In this case, y=6-x and a=5.
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Miracrown (miracrown):
After that, we can solve for x
OpenStudy (dtan5457):
So to get rid of it, is it 6-x>5 and 6-x<-5?
Miracrown (miracrown):
it is not "and," it is "or."
Miracrown (miracrown):
6-x>5 ''OR'' 6-x<-5
OpenStudy (dtan5457):
Yes, my mistake
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OpenStudy (dtan5457):
Now just solve for x?
Miracrown (miracrown):
Yep
OpenStudy (dtan5457):
x>11
x>1?
OpenStudy (dtan5457):
you do switch the sign from -x<-1 right?
Miracrown (miracrown):
Absolutely
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OpenStudy (dtan5457):
So basically it's just x>1
OpenStudy (dtan5457):
Well I mean >11
OpenStudy (dtan5457):
as that satisfies both?
Miracrown (miracrown):
-5-6=-11
Miracrown (miracrown):
x>11 or x<1
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Miracrown (miracrown):
Satisfies either. Cannot satisfy both
OpenStudy (dtan5457):
Forgot to switch the sign when taking out the absolute value
Miracrown (miracrown):
|dw:1421724792719:dw|