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Mathematics 8 Online
OpenStudy (dtan5457):

How do I solve absolute value inequalities like this again?

OpenStudy (dtan5457):

\[-3\left| 6-x \right|<-15\]

Miracrown (miracrown):

Divide -3 on both sides first

OpenStudy (dtan5457):

do i divide inside the absolute value too?

OpenStudy (dtan5457):

completely forgot this..

OpenStudy (freckles):

let u=|6-x| -3u<-15 <--- do you know how to solve this for u?

Miracrown (miracrown):

Then we have |6-x|>5. No, we don't.

OpenStudy (dtan5457):

@freckles Yeah, divide both by -3 and switch the sign

OpenStudy (freckles):

right and you what @Miracrown just posted u>5

Miracrown (miracrown):

We need to get rid of absolute value sign

Miracrown (miracrown):

In this case, y=6-x and a=5.

Miracrown (miracrown):

After that, we can solve for x

OpenStudy (dtan5457):

So to get rid of it, is it 6-x>5 and 6-x<-5?

Miracrown (miracrown):

it is not "and," it is "or."

Miracrown (miracrown):

6-x>5 ''OR'' 6-x<-5

OpenStudy (dtan5457):

Yes, my mistake

OpenStudy (dtan5457):

Now just solve for x?

Miracrown (miracrown):

Yep

OpenStudy (dtan5457):

x>11 x>1?

OpenStudy (dtan5457):

you do switch the sign from -x<-1 right?

Miracrown (miracrown):

Absolutely

OpenStudy (dtan5457):

So basically it's just x>1

OpenStudy (dtan5457):

Well I mean >11

OpenStudy (dtan5457):

as that satisfies both?

Miracrown (miracrown):

-5-6=-11

Miracrown (miracrown):

x>11 or x<1

Miracrown (miracrown):

Satisfies either. Cannot satisfy both

OpenStudy (dtan5457):

Forgot to switch the sign when taking out the absolute value

Miracrown (miracrown):

|dw:1421724792719:dw|

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