a toy rocket is fired from the ground with an upward velocity of 200 feet per second. How many seconds will the rocket take to return to the ground?
can you give the equation for the position of the rocket
h=-16t^2 +v0t+h0, where h is the final height in feet, t is the time of travel in seconds,v0 is the initial velocity in feet per second,and h0 is the initial height in feet of an object traveling upward
stupid question upward velocity means not initial right? and if not, what is the relationship between upward and initial velocity? or what does upward velocity mean exactly?
@ganeshie8 can you tell me what upward velocity means exactly?
it does not specify all i am given is the question and the formula
and pretty please :)
yes its same as the initial velocity before leaving the ground
oh that makes this easier for me to read thank you so much
well we know the rocket started with initial height 0 so we know h0 is 0
\[h=-16t^2+200t\]
we want to know when h is zero again
besides at t=0
0=-16t^2+200t solve for t
thank you and one more question if you could?
post
(a-1)(a+4)=14 p.s I'm really bad at math:(
you will have to make it ugly before you make it pretty
you need everything on one side
and multiply the (a-1)(a+4) and then combine like terms
\[(a-1)(a+4)=14 \\ \text{ subtract 14 on both sides } \\ (a-1)(a+4)-14=0 \\ \text{ multiply the } (a-1)(1+4) \text{ then subtract the 14 there }\]
thank you so much :)
np :)
like if you still need help on solving it let me know
i will be here for a few more minutes
I'm done for tonight but thanks for all your help
np :) gave a good night
have*
thanks, if you need help in english i can help lol thats my best subject
i feel like you are making fun of my english a little bit :p just kidding
you can make fun of my math :)
i might
:) night
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