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Mathematics 13 Online
OpenStudy (anonymous):

Can anybody help me with a problem? here is the graph to it and stuff: http://imgur.com/a/VmfYN I know that the lowest parts would be under the graph (x>2) and the largest integral would be the non negative part (2>x) but im confused as how they want me to set up an equation and solve it.

OpenStudy (anonymous):

so would my "largest" equation be int(2,0) f(t) dx and my "smallest" be int(2,5) f(t) dx?

OpenStudy (anonymous):

beacue for me to get a "large" equation i would have to put my lower bound on top, where x is.

ganeshie8 (ganeshie8):

do you mean "maximum" value would be : \[\int_0^2f(t)~dt\]

ganeshie8 (ganeshie8):

?

OpenStudy (anonymous):

yes, but our sheet states int(2,x) f(t) dt

OpenStudy (anonymous):

so wouldnt it have to be a number backwards from 2 on top?

OpenStudy (anonymous):

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