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How many permutations can be made of the letters of the word "radar" when taken all at a time? 30 24
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@ganeshie8
30?
Permutations (arrangements) of n objects where p of one type are alike, q of another type are alike, r of another type are alike and so on is given by\[\frac{ n! }{ p!q!r!... }\]
Example: If we consider the # of permutations of the word TORONTO taken all at a time, then we notice there are 7 letters of which there are 2 T's and 3 O's. Thus the total # of permutations possible are\[\frac{ 7! }{ 2!3! }=210 \]
CORRECTION:\[\frac{ 7! }{ 2!3! }=420\]
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Yes @hhelpplzzzz your answer of 30 is correct because RADAR has 5 letters of which there are 2 A's and 2 R's. Thus\[\frac{ 5! }{ 2!2! }=30\]
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