Simplify square root parenthesis 1 minus cosine theta parenthesis times parenthesis 1 plus cosine theta parenthesis divided by cosine squared theta.

square root sine theta
±sin Θ

Question

Simplify square root parenthesis 1 minus cosine theta parenthesis times parenthesis 1 plus cosine theta parenthesis divided by cosine squared theta.

 square root sine theta
 ±sin Θ<------ MY ANSWER
 ±cos Θ
 |tan Θ|
CAN ANYONE PLEASE CHECK IF I GOT THIS RIGHT?!!!

anonymous · Answer

@e.mccormick

e.mccormick · Answer

$\sqrt{1 - \cos\theta} \cdot \dfrac{1 +\cos \theta }{ \cos^2 \theta}$

That?

e.mccormick · Answer

Or looking at where you said parenthesis it could be...

$\dfrac{\sqrt{(1 - \cos\theta)(1 +\cos \theta )} }{ \cos^2 \theta}$

anonymous · Answer

@ganeshie8

anonymous · Answer

@ganeshie8 @ganeshie8

e.mccormick · Answer

Still need to know what the equation is supposed to be...  You just wrote parenthesis  so I di not know what opens and closes.