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Mathematics 16 Online
OpenStudy (anonymous):

Simple problem medal and fan.

OpenStudy (anonymous):

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OpenStudy (misty1212):

HI!! does "simplify" mean "add"?

OpenStudy (anonymous):

Simplify after you add I think.

OpenStudy (misty1212):

lol probably cannot but in any case the common denominator for \(mn\) and \(n^2\) is \(mn^2\)

OpenStudy (misty1212):

\[\frac{2}{mn}\times \frac{n}{n}+\frac{m^2}{n^2}\times \frac{m}{m}\] is a start

OpenStudy (anonymous):

Says you.

OpenStudy (misty1212):

yes, says i lol

OpenStudy (anonymous):

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