I'm supposed to find the value of x, can someone check my work? (I'll post it in the comments)
x(x+1) = x^2+x
@Directrix help
This answer is not correct. I see where the algebra error happened. Just a second.
Ok thank you. I knew something wasn't right but I'm not sure what
I marked the first error. See attachment.
The first line of work is the quantity (x + 5) times the quantity (x -2). On the right side, x times the quantity (x+1) = x² + 1*x x times x = x² 2 * x = 2x
So (x + 5)(x - 2) = x (x + 1) x^2 - 2x + 5x - 10 = x^2 + x x^2 + 7x - 10 = x^2 + x
Take a second look at this: - 2x + 5x --> The sum is not 7x but what?
Oh okay its 3x. Sorry I wasn't paying attention It would be: x^2 + 3x - 10 = x^2 + x
Good. What is the next step?
Okay...now I need to get x by itself?
Subtract the x^2 terms off both sides first.
x^2 + 3x - 10 = x^2 + x -x^2 -x^2 ----------------------------- 3x - 10 = x If you agree with that, you can collect the x terms on one side now.
So I would subtract 3x from both sides and get: -10 = -2x
Correct.
Last step: solve for x.
Add 2 to -10 and get -8 = x
That is not a 2. It is -2x.
-10 = -2x You can divide by sides by -2 to solve for x.
But the options given to me are 2.5, 5, 7.5, and 10 Also I see where I made my mistake.
Divide by -2 because we are looking for x, not -2x.
The answer would be 5 correct?
We are not at the answer stage. Solve for x.
x = 5, correct.
Thank you so much. As you can probably see, I'm not very good at math.
Your skills are better than most users here. So, keep working.
I will thank you ^-^
You are welcome.
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