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Help with trig practice problems
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Posting question one moment
SORRY NOT MY GRADE LEVEL
so first step is \[\sqrt(1/2^2+-3/2^2)\]
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OK
loool ok
thanks though
\[\sqrt1/4+3/4 = \sqrt1 \]
@kl0723
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since you're given the values just make sure to know that \[\csc(\Theta)\] is either the 1/sin of theta or it could be useful to know also that it equals to the hypotenuse over the opposite side
|dw:1421802905876:dw|
So for this with csc I have to use r/y r being the hypotenuse
and this is what I use the points for
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Yes but a negative squared is positive though
i mean yes you will use it r/y
buht like the square root to find the hypotenuse
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