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Mathematics 6 Online
OpenStudy (darkbluechocobo):

Help with trig practice problems

OpenStudy (anonymous):

?

OpenStudy (darkbluechocobo):

Posting question one moment

OpenStudy (darkbluechocobo):

OpenStudy (anonymous):

SORRY NOT MY GRADE LEVEL

OpenStudy (darkbluechocobo):

so first step is \[\sqrt(1/2^2+-3/2^2)\]

OpenStudy (anonymous):

OK

OpenStudy (darkbluechocobo):

loool ok

OpenStudy (darkbluechocobo):

thanks though

OpenStudy (darkbluechocobo):

\[\sqrt1/4+3/4 = \sqrt1 \]

OpenStudy (darkbluechocobo):

@kl0723

OpenStudy (kl0723):

since you're given the values just make sure to know that \[\csc(\Theta)\] is either the 1/sin of theta or it could be useful to know also that it equals to the hypotenuse over the opposite side

OpenStudy (kl0723):

|dw:1421802905876:dw|

OpenStudy (darkbluechocobo):

So for this with csc I have to use r/y r being the hypotenuse

OpenStudy (darkbluechocobo):

and this is what I use the points for

OpenStudy (darkbluechocobo):

OpenStudy (darkbluechocobo):

Yes but a negative squared is positive though

OpenStudy (darkbluechocobo):

i mean yes you will use it r/y

OpenStudy (darkbluechocobo):

buht like the square root to find the hypotenuse

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