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Will medal and fan: Try to fill in the blanks to create other pythagorean triples: a. 9,__,__ b. 11,__,__ c. 13,__,__ alright so I know how to get the third blank but how do I know the 2nd blank?? I have the answer key
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oh, has to be integers
no roots, only integers
yep
@SkepticGod - You can find the list of pythagorean triples on the link I sent to you.
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well i can't just pick for the second blank the answers were: a. 9,40,41 b. 11,60,61 c. 13,84,85
9, 12, 15 works for a also
\[11^{2} + b ^{2} = c ^{2} \space => 11^{2} (c-b) \space (c+b)\]
both c-b and c+b are factors of 11^2. We know that 1, 11, 11^2 are all possible factors of 11^2.
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