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AP Math
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find polar coordinates for three different points that line on the graph of the equation r=-4cosθ. I have (-4,0) but i can't find the other two.
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plugin \(\theta = \dfrac{\pi}{2}\), you get \(r = -4\cos(\dfrac{\pi}{2}) = -4*0 = 0\) so (0, pi/2) is another point on the given graph
similarly see if you can find another point by plugging in \(\large \theta = \dfrac{\pi}{6}\)
almost -4 (3.999) so the next point would be (-4, pi/6)?
doesn't look correct
\(r = -4\cos(\theta)\) plugin \(\theta = \dfrac{\pi}{6}\) \(r = -4\cos(\dfrac{\pi}{6}) = -4*\dfrac{1}{2} = -2\) so (-2, pi/6) is another point on the graph
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had the calculator in degree mode...
you're using the unit circle aren't you?
cos(pi/3)= 1/2...
thank you
thats it!
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