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Find all the zeros of the equation -3x^4+27x^2+1200=0 Stuck-- all I know is that there are 4 zeros... I think.
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-3(x-5)(x^2+16)(x+5) Start with that
What do I do?
How did you get to that?
ok so the zeros are what you can add to each number in the parenthesis to give you zero, so for example your first zero is 5, because 5-5=0
so +/- 5 and +/- 4
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your zeroes are 5, -5, 4i, -4i
How did you get i?
And how did you get the very first equation you wrote?
well do you know how to factor?
Yes.
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I just factored out your original equation, once you factor out the equation your result is-3(x-5)(x^2+16)(x+5
Where did the 1200 go?
-3*-5*16*5 = 1200
Ooookay. I am apparently worse at this than I thought! Thank you.
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