Find an equation of the plane consisting of all points that are equidistant from (1, -3, 5) and (2, 3, -2).

Question

ganeshie8 · Answer

you need a `point` and a `normal vector` to write equation of plane

anonymous · Answer

hmm ok , well I have 2 points

ganeshie8 · Answer

the plane doens't go through those points, so you cant use them directly.

however the point is almost readily available to you - simply take the midpoint of given points

anonymous · Answer

(1.5,0,1.5)

ganeshie8 · Answer

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ganeshie8 · Answer

Notice that the plane passes through the midpoint of given points

ganeshie8 · Answer

why ?

anonymous · Answer

once you explain it it makes more sense, but i never pick up this stuff on my own, im just not getting it

ganeshie8 · Answer

by definition, midpoint stays at same distance between both the given points, yes ?

anonymous · Answer

sorry im reading and trying to understand previous posts

ganeshie8 · Answer

take your time

anonymous · Answer

"the plane doens't go through those points, so you cant use them directly." i dont understand why the plane doesnt go through the points

anonymous · Answer

how do i know that?

ganeshie8 · Answer

before answering that question, let me ask you a side question

anonymous · Answer

k

ganeshie8 · Answer

what are we trying to find here exactly ?

anonymous · Answer

equation of a plane

ganeshie8 · Answer

what plane ?

anonymous · Answer

plane consisting of all points that are equidistant from (1, -3, 5) and (2, 3, -2).   dont really know what that means, i assume equidistant means equal distance?

ganeshie8 · Answer

we want the equation of plane that stays at same distance from both the given points

ganeshie8 · Answer

would you agree that the midpoint stays at same distance from both the given points ?

anonymous · Answer

i wouldnt say it stays at same distance, but i guess it is at the same distance?

ganeshie8 · Answer

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