What are the points of discontinuity? Are they all removable?

Question

highschoolmom2010 · Answer

$$\frac{ \left( x-5 \right) }{x^2-6x+5}$$

highschoolmom2010 · Answer

@ganeshie8

anonymous · Answer

set the denominator equal to zero and solve for $x$

ganeshie8 · Answer

discontinuity occurs when the given rational expression becomes undefined

rational expression becomes undefined when the denominator becomes 0

ganeshie8 · Answer

simply set the denominator equal to 0 and solve x for discontinuities

ganeshie8 · Answer

$$\large x^2 - 6x + 5 = 0$$

see if you can solve $\large x$

highschoolmom2010 · Answer

i have gotten to 
$$x^2-6x+5=0$$
$$x^2-6x+5-5=0-5$$
$$x^2-6x=5$$
now i am confused on where to go next with this

ganeshie8 · Answer

quadratics wont work like that,  try to factor it instead

ganeshie8 · Answer

remember factoring ?

highschoolmom2010 · Answer

ah ok 
(x+6 )(x-1)

ganeshie8 · Answer

$$\large x^2 - 6x +5 = 0$$

$$\large (x-5)(x-1) = 0$$

highschoolmom2010 · Answer

wait i thought |dw:1421944865308:dw|

ganeshie8 · Answer

its the opposite actually... find two number such that they : 

1) add up to -6
2) multiply to 5